5d^2+28d-180=00

Solution for 5d^2+28d-180=00 equation:

5d^2+28d-180=00

a = 5; b = 28; c = -180;
Δ = b2-4ac
Δ = 282-4·5·(-180)
Δ = 4384
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$d_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$d_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{4384}=\sqrt{16*274}=\sqrt{16}*\sqrt{274}=4\sqrt{274}$
$d_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(28)-4\sqrt{274}}{2*5}=\frac{-28-4\sqrt{274}}{10}
$
$d_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(28)+4\sqrt{274}}{2*5}=\frac{-28+4\sqrt{274}}{10}
$